Questions
A projectile is fired at an angle of 45° with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection, is :
detailed solution
Correct option is C
tanθ=HmaxR/2=u2sin245°2g2u2sin45°cos45°2gtan45°2=12θ=tan−112Talk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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