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Q.

A projectile is fired at an angle of 45° with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection, is :

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a

45°

b

60°

c

tan-112

d

tan-132

answer is C.

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Detailed Solution

tanθ=HmaxR/2=u2sin245°2g2u2sin45°cos45°2gtan45°2=12θ=tan−112

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A projectile is fired at an angle of 45° with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection, is :