Questions
A projectile is fired at an angle of with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection is
detailed solution
Correct option is B
Height of projectileH = u2sin2θ2g = u2sin24502g⇒ H = u24g ------(i)Range of projectile R = u2sin 2θg = u2sin 900g⇒R = u2g tan α = HR2In ∆OAB = u24gu22g tan α =12 ⇒ α = tan-1(12)Talk to our academic expert!
Similar Questions
A ball is projected obliquely with a velocity 49 ms–1 strikes the ground at a distance of 245 m from the point of projection. It remained in air for
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