A projectile is fired from level ground at an angle θ above the horizontal. The elevation angle ϕ of the highest point as seen from the launch point is related to θ by the relation

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tan⁡ϕ=14tan⁡θ

tan⁡ϕ=tan⁡θ

tan⁡ϕ=12tan⁡θ

tan⁡ϕ=2tan⁡θ

answer is C.

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Detailed Solution

See fig. From figuretan⁡ϕ=h/(R/2)tan⁡ϕ=u2sin2⁡θ/2gu2sin⁡2θ/2g=sin2⁡θsin⁡2θ=sin2⁡θ2sin⁡θcos⁡θ=sin⁡θ2cos⁡θ=12tan⁡θ

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