A projectile is fired from level ground at an angle $\mathrm{\theta }$ above the horizontal. The elevation angle $\mathrm{\varphi }$ of the highest point as seen from the launch point is related to $\mathrm{\theta }$ by the relation:

• A

  $\tan \mathrm{\varphi }=\frac{1}{4}\tan \mathrm{\theta }$

• B

  $\tan \mathrm{\varphi }=\tan \mathrm{\theta }$

• C

  $\tan \mathrm{\varphi }=\frac{1}{2}\tan \mathrm{\theta }$

• D

  $\tan \mathrm{\varphi }=2\tan \mathrm{\theta }$