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Q.

A projectile is fired from surface of earth with velocity kve where ve is escape velocity and k < 1. Find the maximum height upto which the projectile will rise from the centre of earth.

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a

Rk2+1

b

Rk21−k2

c

Rk2+1

d

R1−k2

answer is D.

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Detailed Solution

−GMmh=−GMmR+12mkve2GMm1R−1h=12mk2ve2GMmR−12m2GMRk2=GMmh1R1−k2=1h    ∴h=R1−k2
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