Q.
A projectile is fired from the surface of the earth with a velocity of 5 ms-1and angle θ with the horizontal. Another projectile fired from another planet with a velocity of 3 ms-1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (ms-2) is (Given g = ms-2
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a
3.5
b
5.9
c
16.3
d
110.8
answer is A.
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Detailed Solution
The equation of trajectory is y=xtanθ−gx22u2cos2θwhere θ is the angle of projection and u is the velocity with which projectile is projected. For equal trajectories for same angles of projection, gu2= constant As per question 9.852=g′32where g' is acceleration due to the gravity on the planet. g′=9.8×925=3.5ms−2
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