A projectile is fired from the surface of the earth with a velocity of $$5$$ $$ms-1$$ and angle θ with the horizontal. Another projectile fired from another planet with a velocity of $$3$$ $$ms-1$$ at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in$$ $$ms-2$$ $$) $$(given$$ g $$=$$ $$9.8m/s)2$$

Question

A projectile is fired from the surface of the earth with a velocity of $$5$$ $$ms-1$$ and angle θ with the horizontal. Another projectile fired from another planet with a velocity of $$3$$ $$ms-1$$ at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in$$ $$ms-2$$ $$) $$(given$$ g $$=$$ $$9.8m/s)2$$

Infinity Learn · Accepted Answer

As range $$=$$ $$u2sin2$$θg, So, g∝$$u2Therefore$$, $$gplanet=3529.8m/s2=3.5m/s2$$

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