A projectile is fired on a horizontal ground. Variation of slope of its trajectory with horizontal displacement is shown in figure. (Take, g = 10 m/s2)

y=xtan⁡θ−gx22u2cos2⁡θ Slope =dydx=tan⁡θ     At x=0; Slope =tan⁡θ=1       θ=45∘ At  x=10; Slope =10tan45−g(10)2u2cos2⁡θ=0   u2cos2⁡θ=100⇒   ucos⁡θ=10⇒   u=102m/s    R=u2sin⁡2θg=20m    T=2usin⁡θg=2s∫( slope )dx=∫dy= vertical displacement