Questions
A projectile is fired horizontally with a velocity 20m/s from the top of a hill of high 490m velocity after 2sec is
a
20 m/s
b
202 m/s
c
30 m/sec
d
302 m/sec
detailed solution
Correct option is B
horizontal component of velocity=Vx=Ux⇒Vx=20m/sec Vertical component of velocity=Vy=Uy-gt ; given time t=2sec Vy=0-10(2)=-20m/secV=Vxi⏜+Vyj⏞ ;substitute obtained valuesV=20i⏞-20j⏞|V→|=Vx2+Vy2|V→|=202+202|V→|=202m/secTalk to our academic expert!
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