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A projectile is fired at a speed of
detailed solution
Correct option is B
At the highest point, the projectile has horizontal velocity. The lighter part comes to rest. Hence, the heavier part will move with increased horizontal velocity. In vertical direction, both parts have zero velocity and undergo same acceleration. Thus, both will hit the ground together. As internal forces do not affect the motion of the centre of mass, the centre of mass hits the ground at the position where the original projectile would have landed. The range of the original projectile is. xcm=2u2sinθcosθg=2×104×35×4510m=960 m The centre of mass will hit the ground at this position. As the smaller block comes to rest after breaking it falls down vertically and hits the ground at half of the range, i.e, at x=480 m. If the heavier block hits the ground at x2, then xcm=m1x1+m2x2m1+m2 ⇒ 960 =(m)(480)+(3m)(x2)(m+3m) ⇒ x2=1120 mTalk to our academic expert!
Similar Questions
A shell is fired from a cannon with velocity v m/sec at an angle with the horizontal direction. At the highest point in its path it explodes into two pieces of equal mass. One of the pieces retraces its path to the cannon and the speed in m/sec of the other piece immediately after the explosion is
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