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A projectile is fired vertically from the surface of earth with a speed $\sqrt{gR}$ . Where R is the radius of earth. How far above the earth’s surface would the projectile go?

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Correct option is A

Conserving energy, 12mu2−GMmR=−GMmR+h⇒12GMR2.R2=GMR−GMR+h=GM.hR+hR Solving, h = R

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A projectile is fired vertically from the surface of earth with a speed gR. Where R is the radius of earth. How far above the earth’s surface would the projectile go?

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Ready to Test Your Skills?

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A projectile is fired vertically from the surface of earth with a speed $\sqrt{gR}$ . Where R is the radius of earth. How far above the earth’s surface would the projectile go?