A projectile is fired vertically from the surface of earth with a speed gR. Where R is the radius of earth. How far above the earth’s surface would the projectile go?
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a
R
b
R2
c
2R
d
3R2
answer is A.
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Detailed Solution
Conserving energy, 12mu2−GMmR=−GMmR+h⇒12GMR2.R2=GMR−GMR+h=GM.hR+hR Solving, h = R