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Q.

A projectile is fired vertically upwards with an initial velocity u. After an interval of T seconds, a second projectile is fired vertically upwards, also with initial velocity u.

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a

They meet at time t=ug and at a height u22g+gT28

b

They meet at time t=ug+T2 and at a height u22g+gT28

c

They meet at time t=ug+T2 and at a height u22g−gT28

d

They never meet

answer is C.

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Detailed Solution

For first projectile, h1=ut−12gt2 For second projectile, h2=u(t−T)−12g(t−T)2 When both meet i.e. h1=h2 :  ut−12gt2=u(t−T)−12g(t−T)2⇒ uT+12gT2=gtT⇒ t=ug+T2 and  h1=uug+T2−12gu2+T22=u22g−gT28
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