A projectile is fired vertically upwards with an initial velocity u. After an interval of T seconds, a second projectile is fired vertically upwards, also with initial velocity u.
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a
They meet at time t=ug and at a height u22g+gT28
b
They meet at time t=ug+T2 and at a height u22g+gT28
c
They meet at time t=ug+T2 and at a height u22g−gT28
d
They never meet
answer is C.
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Detailed Solution
For first projectile, h1=ut−12gt2 For second projectile, h2=u(t−T)−12g(t−T)2 When both meet i.e. h1=h2 : ut−12gt2=u(t−T)−12g(t−T)2⇒ uT+12gT2=gtT⇒ t=ug+T2 and h1=uug+T2−12gu2+T22=u22g−gT28