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Questions  

A projectile is fired with velocity u making angle θ with the horizontal. What is the angular momentum of the projectile at the highest point about the starting point ? Given that mass of the projectile is m

a
mcos⁡θ2g
b
mu3sin2⁡θcos⁡θ4g
c
mu3cos2⁡θ2g
d
mu3sin2⁡θcos⁡θ2g

detailed solution

Correct option is D

Maximum height, h=u2sin2⁡θ2gLinear momentum at highest point =mucos⁡θAngular momentum of the projectile at the highest point= linear momentum × perpendicular distance =mucos⁡θ×h=mucos⁡θ×u2sin2⁡θ/2g =mu3sin2⁡θcos⁡θ2g

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Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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