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Q.

A projectile is fired with velocity u making angle θ with the horizontal. What is the angular momentum of the projectile at the highest point about the starting point ? Given that mass of the projectile is m

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a

mcos⁡θ2g

b

mu3sin2⁡θcos⁡θ4g

c

mu3cos2⁡θ2g

d

mu3sin2⁡θcos⁡θ2g

answer is D.

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Detailed Solution

Maximum height, h=u2sin2⁡θ2gLinear momentum at highest point =mucos⁡θAngular momentum of the projectile at the highest point= linear momentum × perpendicular distance =mucos⁡θ×h=mucos⁡θ×u2sin2⁡θ/2g =mu3sin2⁡θcos⁡θ2g
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