Q.
A projectile is fired with velocity u making angle θ with the horizontal. What is the angular momentum of the projectile at the highest point about the starting point ? Given that mass of the projectile is m
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a
mcosθ2g
b
mu3sin2θcosθ4g
c
mu3cos2θ2g
d
mu3sin2θcosθ2g
answer is D.
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Detailed Solution
Maximum height, h=u2sin2θ2gLinear momentum at highest point =mucosθAngular momentum of the projectile at the highest point= linear momentum × perpendicular distance =mucosθ×h=mucosθ×u2sin2θ/2g =mu3sin2θcosθ2g
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