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Q.

A projectile is fired with a velocity v at right angle to the slope inclined at an angle θ with the horizontal. The range of the projectile along the inclined plane is

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a

2v2tan⁡θg

b

v2sec⁡θg

c

2v2tan⁡θsec⁡θg

d

v2sin⁡θg

answer is C.

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Detailed Solution

ax=−gsin⁡θ;ay=−gcos⁡θux=0;uy=vAlong y-axis, Sy=uyt+12ayt20=vt−12gcos⁡θt2t=2vgcos⁡θAlong x-axis,Sx=uxt+12axt2 ⇒R=0×t−12gsin⁡θ2vgcos⁡θ2⇒R=2v2tan⁡θsec⁡θg
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