A projectile is given an initial velocity of i^+2j^ The cartesian equation of its path is :g=10m/s2
y=2x−5x2
y=x−5x2
4y=2x−5x2
y=2x−25x2
tanθ=usinθucosθ=21
The desired equation is,
y=xtanθ−gx22u2cos2θ=x(2)−10x2222+122152 or y=2x−5x2