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Questions  

A projectile is given an initial velocity of i^+2j^ The cartesian equation of its path is :g=10m/s2

a
y=2x−5x2
b
y=x−5x2
c
4y=2x−5x2
d
y=2x−25x2

detailed solution

Correct option is A

tan⁡θ=usin⁡θucos⁡θ=21The desired equation is,y=xtan⁡θ−gx22u2cos2⁡θ=x(2)−10x2222+122152  or  y=2x−5x2

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