A projectile is given an initial velocity of i^+2j^ The cartesian equation of its path is : (g = 10 m/ s2)
y = 2x - 5x2
y = x - 5x2
4y = 2x - 5x2
y = 2x - 25x2
tanθ=usinθucosθ=21The desired equation is,y=xtanθ−gx22u2cos2θ=x(2)−10x2212or y = 2x - 5x2.