First slide
Projectile motion
Question

A projectile is given an initial velocity of i^+2j^ . The Cartesian equation of its path is: (g=10 m/s2)

Moderate
Solution

u=uxi^+uyj^=ucosθi^+usinθj^=i^+2j^

 tanθ=usinθucosθ=21 , cosθ=15

The desired equation is,y=xtanθgx22u2cos2θ

=x×210x22(22+12)2(15)2

or y=2x5x2

 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App