A projectile is given an initial velocity of i^+2j^ . The Cartesian equation of its path is: (g=10 m/s2)
y=2x−5x2
y=x−5x2
4y=2x−5x2
y=2x−25x2
u→=uxi^+uyj^=ucosθi^+usinθj^=i^+2j^
∴ tanθ=usinθucosθ=21 , cosθ=15
The desired equation is,y=xtanθ−gx22u2cos2θ
=x×2−10x22(22+12)2(15)2
or y=2x−5x2