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Q.

A projectile is given an initial velocity (i^ +2j ^ ) m/s .  The cartesian equation of its path is (g =10ms-2)                             (JEE MAIN - 2013)

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a

y = 2x - 5x2

b

9y =12x - 5x2

c

y = 9x - 5x2

d

5y = x -9x2

answer is A.

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Detailed Solution

u cos θ =1, usin θ = 2Therefore tan θ = 2 ,sin 2θ = 45 and R =u2 sin 2θg = 25 The equation of the trajectory  is given by  y =x tan θ (1 - xR) = 2x -5x2
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