A projectile goes farthest from the earth when the angle an projection is:
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a
0o
b
45o
c
90o
d
180o
answer is C.
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Detailed Solution
In vertical direction,ui=u sinθ, uf=0 uf2−ui2=−2gs0−u2sin2θ=−2gss=u2sin2θ2gwhere s is the maximum height.For s to be maximum, sinθ should be maximum, i. e., θ = 90°.