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A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of 3ms-2 for 0.5 minutes. If the maximum height reached by it is 80m then the angle of projection is [g =10ms-2]

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a

tan-1(3)

b

tan-132

c

tan-149

d

sin-149

answer is C.

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Detailed Solution

H=u2sin2θ2g u cos θ=3×30 m/s = 90 m/s . u sin θ =2gh =2×10×80 m/s =40 m/s tan θ =49

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A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of 3ms-2 for 0.5 minutes. If the maximum height reached by it is 80m then the angle of projection is [g =10ms-2]