Question

A projectile has the maximum range 500 m. If the projectile is thrown up a smooth inclined plane of 30⁰ with the same (magnitude) velocity, the distance covered by it along the inclined plane till it stops will be

Moderate

Solution

$R_{\max} = \frac{u^{2}}{g} = 500$
Now, $s = \frac{u^{2}}{2 a} = \frac{u^{2}}{2 g \sin 30 °} = \frac{u^{2}}{g} = 500 m$

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