Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A projectile of mass m is launched with an initial velocity vi→ making an angle θ with the horizontal as shown in figure. The projectile moves in the gravitational field of the Earth. The angular momentum of the projectile about the origin when it is at the highest point of its trajectory is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

-mvi3 sin2θ cos θ2gk^

b

mvi3sin2θ cos θ2gk^

c

-mvi3sin θ2cos θgk^

d

2mvi3sin θ2 cos θ gk^

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

At the highest point of the trajectory,x = 12R = vi2sin 2θ2g and y = hmax = (vi sin θ)22gThe angular momentum is thenL1→ = r1→×mv1→      = [vi2sin 2θ2gi^+(visin θ)22gj^]×mvxii^      = -mvi3sin2θcos θ2gk^
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring