First slide
Projection Under uniform Acceleration
Question

A projectile passes two points A and B at same height after 2 s and 6 s of its projection. Horizontal separation between the points A and B is 120 m. The horizontal range is closest to:[g=10m/s2]

Easy
Solution

Time of flight Tf = 2+ 6 = 8 s
For horizontal motion A to B :Δt=4s
So, ux=120m4s=30m/s
Range = 30 x 8 = 240m

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