Q.

A projectile is projected at an angle of 45° to the horizontal. The slope of trajectory of the body varies with time t as

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a

b

c

d

answer is D.

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Detailed Solution

Equation of a projectile y= xtanθ-12gx2u2cos2θ dydt=dxdt tanθ-gxu2cos2θdxdt  dxdt  is constant which is = ucosθ.  So as x inreases with time dydt decreases.
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A projectile is projected at an angle of 45° to the horizontal. The slope of trajectory of the body varies with time t as