A projectile is projected with initial velocity 6 i^+8j^m/s.If g = 10 m/s2, then what is the horizontal range of the projectile?

Initial velocity is 6 i^+8j^m/s (given).Magnitude of velocity of projection is u=ux2+uy2=62+82=10 m/sAngle of projection tanθ=uyux=86⇒sinθ=45  and  cosθ=35Now the horizontal range is, R=u2sin 2θg=u22sin θ cos θg=102×2×4/5×3/510=9.6 m