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A projectile is projected with initial velocity 6i^+8j^m/s.If g = 10 m/s2, then what is the horizontal range of the projectile?

a
8.8 m
b
13.5 m
c
9.6 m
d
11.2 m

detailed solution

Correct option is C

Initial velocity is 6 i^+8j^m/s (given).Magnitude of velocity of projection is u=ux2+uy2=62+82=10 m/sAngle of projection tanθ=uyux=86⇒sinθ=45  and  cosθ=35Now the horizontal range is, R=u2sin 2θg=u22sin θ cos θg=102×2×4/5×3/510=9.6 m

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