A projectile is projected with initial velocity (6i^+8j^)m/s. If g=10m/s2, then what is the horizontal range of the projectile?

Initial velocity is (6i^+8j^)m/s (given).Magnitude of velocity of projection isu=ux2+uy2=62+82=10m/sAngle of projectiontan⁡θ=uyux=86⇒sin⁡θ=45 and cos⁡θ=35Now the horizontal range is,R=u2sin⁡2θg=u22sin⁡θcos⁡θg=(10)2×2×(4/5)×(3/5)10=9.6m