First slide

Second law

Question

A projectile is projected with a linear momentum p making an angle θ with the horizontal. The change in momentum of the projectile on return to the ground will be

Moderate

A

2 p
B

$2 pcos θ$
C

$2 psin θ$
D

$2 ptan θ$

Solution

The angle made by the projectile with horizontal on return to the earth is $- θ .$ Hence
$Δ p = [i pcos θ + j psin θ] - [i pcos (- θ) + j psin (- θ)]$
$= j 2 p \sin θ$

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