Q.

For a projectile the ratio of maximum height reached to the square of flight time is g=10 ms−2.

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a

5 : 4

b

5 : 2

c

5 : 1

d

10 : 1

answer is A.

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Detailed Solution

H=U2sin2⁡θ2g T2=4U2sin2⁡θg2 HT2=g8=54.
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For a projectile the ratio of maximum height reached to the square of flight time is g=10 ms−2.