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For a projectile the ratio of maximum height reached to the square of flight time is $(g = 10 {ms}^{- 2})$ .

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detailed solution

Correct option is A

H=U2sin2⁡θ2g T2=4U2sin2⁡θg2 HT2=g8=54.

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For a projectile the ratio of maximum height reached to the square of flight time is g=10 ms−2.

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For a projectile the ratio of maximum height reached to the square of flight time is $(g = 10 {ms}^{- 2})$ .