Q.

For the projectile shown in figure,  the time of flight and range along the inclined plane is: (g=10 m/s2)

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a

Range of the projectile along the inclined plane is 145.71mThe time of flight of the projectile along the inclined plane is 1.69s

b

Range of the projectile along the inclined plane is 145.71mThe time of flight of the projectile along the inclined plane is 6.31s

c

Range of the projectile along the inclined plane is 145.71mThe time of flight of the projectile along the inclined plane is 63.1s

d

Range of the projectile along the inclined plane is 129mThe time of flight of the projectile along the inclined plane is 63.1s

answer is B.

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Detailed Solution

time of flight=T=2usinα+βgcosβ T=(2)(202)sin(450+300)(10)cos300 T=(2)(202)sin(750)(10)32=8×1.414×0.963=6.31s range=R=u2gcos2βsin2α+β+sinβ R =(202)2[sin(2×450+300)+sin300](10)cos2300=145.71m
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