First slide

Projection Under uniform Acceleration

Question

A projectile is thrown at an angle of 30° with a velocity of 10 m/s. the change in velocity during the time interval in which it reaches the highest point is

Moderate

Solution

Initial velocity of projection $\large \overrightarrow u = \left( {10\cos {{30}^0}\widehat i + 10\sin {{30}^0}\widehat j} \right)m/s$
$\large = \left( {5\sqrt 3 \widehat i + 5\widehat j} \right)m/s$
Horizontal component of velocity remains unchanged. At the highest point velocity is horizontal and $\large \overrightarrow V = 5\sqrt 3 \widehat {i\;}m/s$
$\large \therefore$ Magnitude of change in velocity $\large = \left| {\overrightarrow {\Delta V} } \right| = \left| {\overrightarrow v - \overrightarrow u } \right| = 5m/s$

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