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A projectile thrown from a tower of height of 9.8 m with horizontal velocity of 2m. The projectile will fall, from the foot of tower at a distance g=9.8m/sec2

a
1 m
b
2 m
c
3 m
d
2m

detailed solution

Correct option is B

given initial velocity horizontally=ux=2m/s; height of tower=h=9.8m/s ;g=9.8m/s2 we know, Range=R=Ux2hg ⇒R=22×9.89.8 R=2m=projectile falling at a distance from foot of tower

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