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A projectile is thrown horizontally with a speed of 20ms1from certain height. If g is 10ms2,then the speed of the projectile after 5 second will be nearly

a
0.5ms−1
b
5ms−1
c
54ms−1
d
500ms−1

detailed solution

Correct option is C

Even after 5 second, the horizontal velocity Vxwill be 20ms−1. The vertical velocity Vy is given by Vy=0+10×5=50ms−1 Now, V=Vx2+Vy2=202+502=54ms−1

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