First slide

Projection Under uniform Acceleration

Question

A projectile is thrown into space so as to have the maximum possible horizontal range equal to 400 m, taking the point of projection as the origin, the coordinates of the point where the velocity of the projectile is minimum, are

Easy

A

400, 100
B

200, 100
C

400, 200
D

200, 200

Solution

Velocity is minimum at the highest point coordinate $(\frac{R}{2}, H)$ .
as $θ = 45^{\circ} H = \frac{R}{4} = 100 m$
So coordinates (200, 100)

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