A projectile is thrown in the upward direction making an angle of $$60$$° with the horizontal direction with a velocity of $$150$$ $$ms-1$$. Then the time after which its inclination with the horizontal is $$45$$° is

Question

Infinity Learn · Accepted Answer

At the two points of the trajectory during projectile motion, the horizontal component of the velocity is same. $$Then150$$×$$12=v$$×$$12$$   or   $$v=1502$$ $$ms-1$$  Initially: $$uy=usin60$$°$$=15032$$ $$ms-1$$  Finally: $$vy=vsin45$$°$$=1502$$×$$12=1502$$ $$ms-1$$  But $$vy=uyy+ayt$$   or   $$1502=15032-10t$$∣ $$10t=1502(3-1)$$   or   $$t=7.5(3-1)$$

A projectile is thrown in the upward direction making an angle of 60° with the horizontal direction with a velocity of 150 ms^-1. Then the time after which its inclination with the horizontal is 45° is

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A projectile is thrown in the upward direction making an angle of 60° with the horizontal direction with a velocity of 150 ms-1. Then the time after which its inclination with the horizontal is 45° is

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A projectile is thrown in the upward direction making an angle of 60° with the horizontal direction with a velocity of 150 ms^-1. Then the time after which its inclination with the horizontal is 45° is