First slide
Projection Under uniform Acceleration

A projectile is thrown in the upward direction making an angle of 60° with the horizontal direction with a velocity of 150 ms-1. Then the time after which its inclination with the horizontal is 45° is


At the two points of the trajectory during projectile motion, the horizontal component of the velocity is same. Then
150×12=v×12   or   v=1502 ms-1  Initially: uy=usin60°=15032 ms-1  Finally: vy=vsin45°=1502×12=1502 ms-1  But vy=uyy+ayt   or   1502=15032-10t 10t=1502(3-1)   or   t=7.5(3-1)

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