First slide

Projection Under uniform Acceleration

Question

A projectile is thrown in the upward direction making an angle of 60° with the horizontal direction with a velocity of 147 m s^-1. Then the time after which its inclination with the horizontal is 45°, is:

Easy

A

15 s
B

10.98 s
C

5.49 s
D

2.745 s

Solution

u_x = u_x = 147 cos 60° and v_y= u_y = gt = 147 sin60° - (9.8) t
If its inclination with the horizontal is 45°, then v_x = u_y
So, $t = \frac{147 (\sqrt{3} - 1)}{2 \times 9.8} = 5.49 s$

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