A projectile is thrown upward with a velocity v0 at an angle α to the horizontal. The change in velocity of the projectile when it strikes the same horizontal plane is
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a
v0 sinα vertically downward
b
2v0 sinα vertically downward
c
2v0 sinα vertically upward
d
Zero
answer is B.
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Detailed Solution
Δv=aΔt (As, a = constant)=(-gj^)2v0sinαg=-2v0sinαj^i.e. Change in velocity is 2v0 sinα, vertically downwards.