A projectile is thrown with some initial velocity at an angle αto the horizontal. Its velocity when it is at the highest point is (2/5)1/2 times the velocity when it is at height half of the maximum height. Find the angle of projection a with the horizontal.
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a
300
b
450
c
600
d
370
answer is C.
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Detailed Solution
(ucosα)=25(ucosα)2+(usinα)2-2gh ….(i)Here, h=H2=u2sin2α4g (ii)Solving Eqs. (i) and (ii), we getα=600.