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Q.

A projectile is thrown with speed v0 at an angle θ with the horizontal plane. It hits a vertical elastic   wall after crossing the maximum height and rebounds with same horizontal velocity and finally falls at a point on the horizontal plane just below the highest point on the trajectory. The total horizontal distance travelled by the projectile is

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a

vθ2sin⁡2θ2g

b

v03sin⁡2θ4g

c

vθ2sin⁡θg

d

v02sin⁡2θg

answer is D.

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Detailed Solution

Since the collision is elastic, dotted line is the mirror image of the actual trajectory after hitting the wall. So, total horizontal distance = range = v02sin⁡2θg
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A projectile is thrown with speed v0 at an angle θ with the horizontal plane. It hits a vertical elastic   wall after crossing the maximum height and rebounds with same horizontal velocity and finally falls at a point on the horizontal plane just below the highest point on the trajectory. The total horizontal distance travelled by the projectile is