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Q.

A projectile is thrown with a velocity of 18 m/s at an angle of 60° with horizontal. The interval between the moments when speed of the projectile is 15 m/s is (g = 10 m/s2)

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answer is 00002.40.

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Detailed Solution

Vx=18cos⁡60∘=9m/s.V1y=152−92=12m/sV2y=−12m/s∴Δt=−12−(12)−10=125sec.
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