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Q.

A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1 kV, its kinetic energy will be

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a

1840 keV

b

1/1840 keV

c

1 keV

d

920 keV

answer is C.

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Detailed Solution

KE=QV=e×103 V=1 keV.
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A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1 kV, its kinetic energy will be