A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1 kV, its kinetic energy will be
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a
1840 keV
b
1 kev
c
1/1840 keV
d
920 keV
answer is B.
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Detailed Solution
When potential difference is tr', energy is given byE=qV=eV ∵qp=qe=eThe above equation shows that kinetic energy is independent of mass of charged particle. Hence, kinetic energy is 1 keV.