First slide

Potential energy

Question

A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1 kV, its kinetic energy will be

Easy

A

1840 keV
B

1 kev
C

1/1840 keV
D

920 keV

Solution

When potential difference is tr', energy is given by
$E = qV = eV (∵ q_{p} = q_{e} = e)$
The above equation shows that kinetic energy is independent of mass of charged particle. Hence, kinetic energy is 1 keV.

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