A proton accelerated by a potential difference $$500$$ kV moves though a transverse magnetic field of $$0.51$$ T as shown in figure. The angle θ through which the proton deviates from the initial direction of its motion, is

Question

A proton accelerated by a potential difference $$500$$ kV moves though a transverse magnetic field of $$0.51$$ T as shown in figure. The angle θ through which the proton deviates from the initial direction of its motion, is

Infinity Learn · Accepted Answer

According to following figure, $$sin$$ θ$$=$$ drAlso,  $$r=$$ $$2mKqB$$  $$=$$  $$1B$$ $$2mVq$$∴     $$sin$$ θ$$=Bd$$ $$q2mV=0.51$$  ×  $$0.1$$  $$1.6$$  ×  $$10$$−$$192$$  × $$1.67$$   × $$10$$−$$27$$ × $$500$$   × $$103=12$$  ⇒  θ$$=$$ $$300$$

A proton accelerated by a potential difference 500 kV moves though a transverse magnetic field of 0.51 T as shown in figure. The angle $θ$ through which the proton deviates from the initial direction of its motion, is

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A proton accelerated by a potential difference 500 kV moves though a transverse magnetic field of 0.51 T as shown in figure. The angle θ through which the proton deviates from the initial direction of its motion, is

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A proton accelerated by a potential difference 500 kV moves though a transverse magnetic field of 0.51 T as shown in figure. The angle $θ$ through which the proton deviates from the initial direction of its motion, is