Questions
A proton accelerated through a potential difference of 100V, has de – Brogile wavelength . The de – Brogile wavelength of an - particle, accelerated through 800 V is
detailed solution
Correct option is D
p22m=qVp=2mqVλ=h2mqVλ1λ2=m2q2V2m1q1V1=4m2q800mq100λ0λ2=64λ2=λo8Talk to our academic expert!
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An electron is orbiting in 4th energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to
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