Questions
A proton is accelerating in a cyclotron having external magnetic field of 0.7 T. If the radii of its dees is 1.8 m, then its maximum kinetic energy (in MeV) is (approximately)
detailed solution
Correct option is C
Kmax=q2B2R22m=1.6×10−122×(0.7)2×(1.8)22×1.67×10−27J=76MeVTalk to our academic expert!
Similar Questions
When a proton is accelerated in a cyclotron device, maximum energy attained by it is 10 MeV. If radius of ‘Dee’ of the cyclotron is doubled and the magnetic field is doubled, then the maximum energy of on α-particle when accelerated in the cyclotron will be
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