Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9
AI Mentor
Check Your IQ
Free Expert Demo
Try Test

Courses

Dropper NEET CourseDropper JEE CourseClass - 12 NEET CourseClass - 12 JEE CourseClass - 11 NEET CourseClass - 11 JEE CourseClass - 10 Foundation NEET CourseClass - 10 Foundation JEE CourseClass - 10 CBSE CourseClass - 9 Foundation NEET CourseClass - 9 Foundation JEE CourseClass -9 CBSE CourseClass - 8 CBSE CourseClass - 7 CBSE CourseClass - 6 CBSE Course
Offline Centres

Q.

A proton beam passes without deviation through a region of space where there are uniform transverse mutually perpendicular electric and magnetic fields with E=120 kV/m and B=50 mT. Then the beam strikes a grounded target. Find the force ( in ×10-5 N) imparted by the beam on the target if the beam current is equal to I = 0.80 mA.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

answer is 2.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Fe=Fm or eE=eBv ∴ v=EB=120×10350×10-3=2.4×106 m/s Let n be the number of protons striking per second.  Then, ne=0.8×10-3 or  n=0.8×10-31.6×10-19=5×1015 m/s Force imparted: Rate of change of momentum = nmv =5×1015×1.67×10-27×2.4×106 =2.0×10-5 N
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring
A proton beam passes without deviation through a region of space where there are uniform transverse mutually perpendicular electric and magnetic fields with E=120 kV/m and B=50 mT. Then the beam strikes a grounded target. Find the force ( in ×10-5 N) imparted by the beam on the target if the beam current is equal to I = 0.80 mA.