First slide

Motion of charged particle in uniform electric field

Question

Proton and deuteron are placed in a uniform electric field and allowed to move for same time. The ratio of their kinetic energies will be

Moderate

A

2:1
B

1:2
C

4:1
D

1:4

Solution

acceleration of the charge particle $\frac{q E}{m}$ and kinetic energy $\frac{1}{2} {(m) (a t)}^{2}$ = $\frac{1}{2} m {(\frac{q E}{m} t)}^{2} = \frac{q^{2} E^{2} t^{2}}{2 m}$ here $\frac{k_{p}}{k_{d}} = (\frac{2}{1}) = 2 : 1$ here q,E,t, are same

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