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Q.

A proton and a deuteron, both having the same kinetic energy, enter perpendicularly into a uniform magnetic field B. For motion of proton and deuteron on circular path of radius Rp and Rd, respectively, the correct option is

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a

Rd =  2 Rp

b

Rd =Rp / 2

c

Rd =Rp

d

Rd =2Rp

answer is A.

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Detailed Solution

We know, mv2R  = qvB.  For  proton,Rp =  mvqB =  2mpKqBand  for  deuteron  Rd =  2mdKqB⇒  RdRp = mdmp   =  2 ⇒ Rd =  2  Rp
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