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A proton and a deuteron, both having the same kinetic energy, enter perpendicularly into a uniform magnetic field B. For motion of proton and deuteron on circular path of radius Rp and Rd, respectively, the correct option is

a
Rd =  2 Rp
b
Rd =Rp / 2
c
Rd =Rp
d
Rd =2Rp

detailed solution

Correct option is A

We know, mv2R  = qvB.  For  proton,Rp =  mvqB =  2mpKqBand  for  deuteron  Rd =  2mdKqB⇒  RdRp = mdmp   =  2 ⇒ Rd =  2  Rp

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