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A proton, a deuteron and an $α$ particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to B. What is the ratio of their K.E.?

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1:2:2

2:2:1

1:2:1

1:1:2

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detailed solution

Correct option is D

K.E. gained by charged particle of charge q when accelerated under a potential difference V will be Ek=qV.For a given V, E∝q.For proton, deuteron and α -particle, the ratio of charges is 1: 1: 2

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