A proton and an electron ate accelerated by the same potential difference.If λe and λp denote de Broglie wavelength of electron and proton, then
λe=λp
λe<λp
λe>λp
none of above
12mpvp2=eV or vp=2eV/mp and 12meve2=eV or ve=2eV/me Now λp=hmpvp=hmp2eV/mp =h2eVmp and λe=hmeve=h2eVme